LC Oscillations

An oscillating $\mathrm{LC}$circuit consists of a $75 \mathrm{mH}$ inductor and a $1.2 \mu \mathrm{F}$ capacitor. If the maximum charge to the capacitor is $2.7 \mu \mathrm{C}$. The maximum current in the circuit will be $\mathrm{\_\_\_\_\_\_\_} \mathrm{mA}$.

In an LC oscillating circuit with $L=75 \mathrm{mH}$ and $C=30 \mathrm{\mu F}$, the maximum charge of capacitor is $2.7\times {10}^{-4} \mathrm{C}$. Maximum current through the circuit will be

In the circuit shown in figure $S_1$ is open and, $S_2$ and $S_3$ are closed. The circuit is in steady state. At time $t=0$, switch $S_1$, is closed and $S_2$ and $S_3$ are opened simultaneously. $V=100 \mathrm{V}$, $R=10 \mathrm{\Omega }, C=100 \mathrm{\mu F}, L=0.03 \mathrm{H}$

Find the maximum charge that will appear on the capacitor at any time

A capacitor of capacitance $0.6 \mu \mathrm{F}$ is charged by a $6 \mathrm{V}$ battery. Charged capacitor is now connected to an inductor of inductance $2 \mathrm{mH}$. Then find the current in the circuit when one third energy stored in capacitor converts into the energy stored in inductor.

In L.C oscillation, maximum current in the inductor can be $I$. If at any instant, electric energy and magnetic energy associated with circuit is equal, then current in the inductor at that instant is

In an L-C oscillation maximum charge on capacitor can be $Q_0$. If at any instant electrical energy is $\frac{3}{4}$th of the magnetic energy then the charge on capacitor at that instant is

When current in coil changes from $5 \mathrm{A}$ to $2 \mathrm{A}$ in $0.1 \mathrm{s}$, an average of $50 \mathrm{V}$ is produced. The self-inductance in $\mathrm{Henry}\left(\mathrm{H}\right)$ of the coil is $\frac{n}{3}$. Write the value of $n$.

A capacitor of capacity $2\mathrm{\mu F}$ is charged to a potential difference of $12 \mathrm{V}.$ It is then connected across an inductor of inductance $0.6\mathrm{mH}.$ What is the current (in $\mathrm{mA}$) in the circuit at a time when the potential difference across the capacitor is $6.0 \mathrm{V}?$

The resonance frequency of $LC$ circuit is

A $60\mu \mathrm{F}$ capacitor is charged to $100 \mathrm{volts}$. This charged capacitor is connected across a $1.5\mathrm{mH}$ coil, so that $\mathrm{LC}$ oscillations occur. The maximum current in the coil is:-

In the $\mathrm{AC}$ network shown in figure, the $\mathrm{rms}$ current flowing through the inductor and capacitor are $0.6 \mathrm{A}$ and $0.8 \mathrm{A}$ respectively. Then the current coming out of the source is

A $60 \mathrm{\mu F}$ capacitor is charged to $100$ volts. This charged capacitor is connected across a $15 \mathrm{mH}$ coil, So that $\mathrm{LC}$ oscillations occur. Maximum current in the coil is :

A fully charged capacitor C with initial charge q₀ is connected to a coil of self inductances L at $\mathrm{t} = 0.$The time at which the energy is stored equally between the electric and the magnetic fields is :

In an $LC$ circuit shown in figure, $C=2 \mathrm{F}$ and $L=2 \mathrm{H}$. At time $t=0$, charge on the capacitor is $3$ coulomb and it is decreasing with rate of $\sqrt{4} \mathrm{C} {\mathrm{s}}^{-1}$. Then choose the correct statement.

Two capacitors of capacitance $C_1$ and $C_2$ are charged to a potential difference of $V_1$ and $V_2$ respectively and are connected to an inductor of inductance $L$ as shown in the figure. Initially key $k$ is open. Now key $k$ is closed and current in the circuit starts increasing. When current in the circuit is maximum

In following $L-C$ circuit at $t=0,$ charge on capacitor $q_{\max }=200\mu \mathrm{C},$ what is $\left|\frac{dI}{dt}\right|$ when $q=100 \mu \mathrm{C}$

The natural frequency of the circuit is (in $\mathrm{rad} {\mathrm{s}}^{-1}$),

In series $\mathrm{LCR}$ resonant circuit if both $L$ and $C$ are increased by $20\%$ then new resonant frequency:-

An $\mathrm{LC}$ current contains inductance $L=1 \mu \mathrm{H}$ and capacitance $C=0.01 \mu \mathrm{F}$. The wavelength of electromagnetic wave generated is nearly :-

The resonant frequency of the $L-C$ circuit is $f_0$ before insertion of the dielectric of ${\epsilon }_r=16.$ After inserting the dielectric, the resonant frequency will be :-